What is y^2+1/4 x-5/4 =18y-81 ?

The solution to y^2+1/4 x-5/4 =18y-81 is Parabola with (h,k)=(5,9),p=-1/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^2+1/4 x-5/4 =18y-81

y^{2} + \frac{1}{4} x - \frac{5}{4} = 18 y - 81

(h, k) = (5, 9), p = - \frac{1}{16}

Solution steps

y^{2} + \frac{1}{4} x - \frac{5}{4} = 18 y - 81

Rewrite

y^{2} + \frac{1}{4} x - \frac{5}{4} = 18 y - 81

in the standard form

4 (- \frac{1}{16}) (x - 5) = (y - 9)^{2}

Therefore parabola properties are:

(h, k) = (5, 9), p = - \frac{1}{16}

x = y^{2} + 19

(y - 1)^{2} = 12 (x - 2)

x = y^{2} + 49

(X - 2)^{2} = 24 (Y + 11)

y^{2} - 10 x - 4 y - 14 = 0

What is y^2+1/4 x-5/4 =18y-81 ?
The solution to y^2+1/4 x-5/4 =18y-81 is Parabola with (h,k)=(5,9),p=-1/16