What is -f(x)=-8x^2+6x+1 ?

The solution to -f(x)=-8x^2+6x+1 is Parabola with (h,k)=(3/8 ,-17/8),p= 1/32

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-f(x)=-8x^2+6x+1

- f (x) = - 8 x^{2} + 6 x + 1

(h, k) = (\frac{3}{8}, - \frac{17}{8}), p = \frac{1}{32}

Solution steps

- y = - 8 x^{2} + 6 x + 1

Rewrite

- y = - 8 x^{2} + 6 x + 1

in the standard form

4 \cdot \frac{1}{32} (y - (- \frac{17}{8})) = (x - \frac{3}{8})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{8}, - \frac{17}{8}), p = \frac{1}{32}

y^{(2)} - x - 4 y + 3 = 0

x^{2} + 6 x - 12 y + 69 = 0

(x - 3)^{2} = 4 y

x^{2} + 10 x - 12 y + 13 = 0

f (x) = \frac{2}{3} (x + 3) (x - 1)

What is -f(x)=-8x^2+6x+1 ?
The solution to -f(x)=-8x^2+6x+1 is Parabola with (h,k)=(3/8 ,-17/8),p= 1/32