What is 1/(x^2+k(x))-6=4 ?

The solution to 1/(x^2+k(x))-6=4 is Parabola with (h,k)=(0, 1/10),p=-1/4

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1/(x^2+k(x))-6=4

\frac{1}{x ^{2} + k ( x )} - 6 = 4

(h, k) = (0, \frac{1}{10}), p = - \frac{1}{4}

Solution steps

\frac{1}{x ^{2} + y} - 6 = 4

Rewrite

\frac{1}{x ^{2} + y} - 6 - 4 = 0

in the standard form

4 (- \frac{1}{4}) (y - \frac{1}{10}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{1}{10}), p = - \frac{1}{4}

What is 1/(x^2+k(x))-6=4 ?
The solution to 1/(x^2+k(x))-6=4 is Parabola with (h,k)=(0, 1/10),p=-1/4