What is x=y^2+sqrt((1+25*6)) ?

The solution to x=y^2+sqrt((1+25*6)) is Parabola with (h,k)=(sqrt(151),0),p= 1/4

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x=y^2+sqrt((1+25*6))

x = y^{2} + (1 + 25 \cdot 6)

(h, k) = (151, 0), p = \frac{1}{4}

Solution steps

x = y^{2} + 1 + 25 \cdot 6

Rewrite

x = y^{2} + 1 + 25 \cdot 6

in the standard form:

4 \cdot \frac{1}{4} (x - 151) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (151, 0), p = \frac{1}{4}

8 x = - y^{2} - 4 y + 4

x^{2} - 4 x + 4 - 4 + 12 y = 20

- f (x) = 2 (x)^{2} + x - 1

(x - 1)^{2} + (y - 3) = 9

y^{2} - 6 y + 8 x + 25 = 0

What is x=y^2+sqrt((1+25*6)) ?
The solution to x=y^2+sqrt((1+25*6)) is Parabola with (h,k)=(sqrt(151),0),p= 1/4