y^2-2y-2x+3=0

Lösung

y^{2} - 2 y - 2 x + 3 = 0

(h, k) = (1, 1), p = \frac{1}{2}

Schritte zur Lösung

y^{2} - 2 y - 2 x + 3 = 0

Rewrite

y^{2} - 2 y - 2 x + 3 = 0

in the standard form

4 \cdot \frac{1}{2} (x - 1) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 1), p = \frac{1}{2}

a f (x) = a x^{2} + 1

16 y^{2} = 9 x

\frac{25}{7} y = (x + 4)^{2}

y^{2} + 4 x - 12 y + 4 = 0

(y - (- 5))^{2} = 2 (x - 1)