What is 4y^2-12y+56x+177=0 ?

The solution to 4y^2-12y+56x+177=0 is Parabola with (h,k)=(-3, 3/2),p=-7/2

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4y^2-12y+56x+177=0

4 y^{2} - 12 y + 56 x + 177 = 0

(h, k) = (- 3, \frac{3}{2}), p = - \frac{7}{2}

Solution steps

4 y^{2} - 12 y + 56 x + 177 = 0

Rewrite

4 y^{2} - 12 y + 56 x + 177 = 0

in the standard form

4 (- \frac{7}{2}) (x - (- 3)) = (y - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (- 3, \frac{3}{2}), p = - \frac{7}{2}

3 - 4 x - y^{2} = 0

- 2 x^{2} + 12 x - 8 y - 18 = 0

x^{2} - 2 x - 6 y + 13 = 0

y^{2} + x = 245000

x = y^{2} + 4 y - 2

What is 4y^2-12y+56x+177=0 ?
The solution to 4y^2-12y+56x+177=0 is Parabola with (h,k)=(-3, 3/2),p=-7/2