What is ((x-5)^2)/4-((y+5))/9 =1 ?

The solution to ((x-5)^2)/4-((y+5))/9 =1 is Parabola with (h,k)=(5,-14),p= 1/9

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((x-5)^2)/4-((y+5))/9 =1

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 5 )}{9} = 1

(h, k) = (5, - 14), p = \frac{1}{9}

Solution steps

\frac{( x - 5 ) ^{2}}{4} - \frac{y + 5}{9} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{4} - \frac{y + 5}{9} = 1

in the standard form:

4 \cdot \frac{1}{9} (y - (- 14)) = (x - 5)^{2}

Therefore parabola properties are:

(h, k) = (5, - 14), p = \frac{1}{9}

x^{2} + y = 49

x^{2} - 5 r (x) + 6 < 0

9 x^{2} + 25 = 30 y

x - y^{2} = 17

x - y^{2} = 15

What is ((x-5)^2)/4-((y+5))/9 =1 ?
The solution to ((x-5)^2)/4-((y+5))/9 =1 is Parabola with (h,k)=(5,-14),p= 1/9