What is d=sqrt((x1-x2))^2+(y1+y2)^2 ?

The solution to d=sqrt((x1-x2))^2+(y1+y2)^2 is Parabola with (h,k)=(-d,0),p= 1/36

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d=sqrt((x1-x2))^2+(y1+y2)^2

d = (x 1 - x 2)^{2} + (y 1 + y 2)^{2}

(h, k) = (- d, 0), p = \frac{1}{36}

Solution steps

d = (x \cdot 1 - x \cdot 2)^{2} + (y \cdot 1 + y \cdot 2)^{2}

Rewrite

d = (x \cdot 1 - x \cdot 2)^{2} + (y \cdot 1 + y \cdot 2)^{2}

in the standard form

4 \cdot \frac{1}{36} (x - (- d)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- d, 0), p = \frac{1}{36}

3 y^{2} + 18 y - x + 22 = 0

y^{2} + 24 y = 4 x + 40

2 x^{2} + 6 y - 1 = 0

3 (x + 2) - y = 2 x^{2} + 3 x

y^{2} - 4 x - 4 = 0

What is d=sqrt((x1-x2))^2+(y1+y2)^2 ?
The solution to d=sqrt((x1-x2))^2+(y1+y2)^2 is Parabola with (h,k)=(-d,0),p= 1/36