What is the axis (x^2}{25}+\frac{y^2)/9 =1 ?

The axis (x^2}{25}+\frac{y^2)/9 =1 is semi-major axis a=5, semi-minor axis b=3

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axis (x^2}{25}+\frac{y^2)/9 =1

axis

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

semi - major axis a = 5, semi - minor axis b = 3

Solution steps

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 3

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

x^{2} + y^{2} = 2

x^{2} + y^{2} - 6 x - 8 y = 0

y, y^{2} - x^{2} + 4 x + 8 y + 12 = 0

- 2 x^{2}

What is the axis (x^2}{25}+\frac{y^2)/9 =1 ?
The axis (x^2}{25}+\frac{y^2)/9 =1 is semi-major axis a=5, semi-minor axis b=3