x^2-10x-4y+17=0

Lösung

x^{2} - 10 x - 4 y + 17 = 0

(h, k) = (5, - 2), p = 1

Schritte zur Lösung

x^{2} - 10 x - 4 y + 17 = 0

Rewrite

x^{2} - 10 x - 4 y + 17 = 0

in the standard form

4 \cdot 1 \cdot (y - (- 2)) = (x - 5)^{2}

Therefore parabola properties are:

(h, k) = (5, - 2), p = 1

y^{2} - 20 x = 69

15 x^{2} + 7 y = 13

x = 5 y^{2}

x^{2} = 11 y

(x + 2)^{2} = - 8 y