What is 4x^2+41k(x)+10=0 ?

The solution to 4x^2+41k(x)+10=0 is Parabola with (h,k)=(0,-10/41),p=-41/16

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4x^2+41k(x)+10=0

4 x^{2} + 41 k (x) + 10 = 0

(h, k) = (0, - \frac{10}{41}), p = - \frac{41}{16}

Solution steps

4 x^{2} + 41 y + 10 = 0

Rewrite

4 x^{2} + 41 y + 10 = 0

in the standard form:

4 (- \frac{41}{16}) (y - (- \frac{10}{41})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{10}{41}), p = - \frac{41}{16}

x = 8 - y^{2}

x + y^{2} = 49

16 y^{2} = 120 x - 225

x^{2} + 7 x - k (x) = 0

2 x + y^{2} = 3

What is 4x^2+41k(x)+10=0 ?
The solution to 4x^2+41k(x)+10=0 is Parabola with (h,k)=(0,-10/41),p=-41/16