What is (B-2d+(s^2)/8)e=(B-d)e ?

The solution to (B-2d+(s^2)/8)e=(B-d)e is Parabola with (h,k)=(0,0),p=2

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(B-2d+(s^2)/8)e=(B-d)e

(B - 2 d + \frac{s ^{2}}{8}) e = (B - d) e

(h, k) = (0, 0), p = 2

Solution steps

(B - 2 d + \frac{s ^{2}}{8}) e = (B - d) e

Rewrite

(B - 2 d + \frac{s ^{2}}{8}) e - (B - d) e = 0

in the standard form

4 \cdot 2 (d - 0) = (s - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 2

x = \frac{y ( y + 1 )}{2}

(x + 1)^{2} = 4 (y - 2)

y^{2} = - \frac{9}{2} x

y \geq x^{2} - 3 x - 10

y^{2} = \frac{x}{2}

What is (B-2d+(s^2)/8)e=(B-d)e ?
The solution to (B-2d+(s^2)/8)e=(B-d)e is Parabola with (h,k)=(0,0),p=2