What is 4a+7b+3a-2b+2aa=3 ?

The solution to 4a+7b+3a-2b+2aa=3 is Parabola with (h,k)=(-7/4 , 73/40),p=-5/8

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4a+7b+3a-2b+2aa=3

4 a + 7 b + 3 a - 2 b + 2 aa = 3

(h, k) = (- \frac{7}{4}, \frac{73}{40}), p = - \frac{5}{8}

Solution steps

4 a + 7 b + 3 a - 2 b + 2 aa = 3

Rewrite

4 a + 7 b + 3 a - 2 b + 2 aa = 3

in the standard form

4 (- \frac{5}{8}) (b - \frac{73}{40}) = (a - (- \frac{7}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{4}, \frac{73}{40}), p = - \frac{5}{8}

x + 5 y^{2} - y + 7 = 0

y^{2} = - \frac{4}{3} x

x - 2 y^{2} = 0

- f (x) = 4 (x)^{2} + 4 (x) - 4

x^{2} - 4 y - 2 x - 40 y - 103 = 0

What is 4a+7b+3a-2b+2aa=3 ?
The solution to 4a+7b+3a-2b+2aa=3 is Parabola with (h,k)=(-7/4 , 73/40),p=-5/8