What is 5x+4y-3x^2-4x=-3y ?

The solution to 5x+4y-3x^2-4x=-3y is Parabola with (h,k)=(1/6 ,-1/84),p= 7/12

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5x+4y-3x^2-4x=-3y

5 x + 4 y - 3 x^{2} - 4 x = - 3 y

(h, k) = (\frac{1}{6}, - \frac{1}{84}), p = \frac{7}{12}

Solution steps

5 x + 4 y - 3 x^{2} - 4 x = - 3 y

Rewrite

5 x + 4 y - 3 x^{2} - 4 x = - 3 y

in the standard form

4 \cdot \frac{7}{12} (y - (- \frac{1}{84})) = (x - \frac{1}{6})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{6}, - \frac{1}{84}), p = \frac{7}{12}

4 y = x^{2} + 4 x - 12

y < x^{2} - 12 x + 38

x^{2} - y = 25

4 x^{2} + 8 x + k (x) = 0

x = - 3 y^{2} + 15 y - 18

What is 5x+4y-3x^2-4x=-3y ?
The solution to 5x+4y-3x^2-4x=-3y is Parabola with (h,k)=(1/6 ,-1/84),p= 7/12