What is 2(-y+1)=(1/2 (x-1))^2 ?

The solution to 2(-y+1)=(1/2 (x-1))^2 is Parabola with (h,k)=(1,0),p=-2

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2(-y+1)=(1/2 (x-1))^2

2 (- y + 1) = (\frac{1}{2} (x - 1))^{2}

(h, k) = (1, 0), p = - 2

Solution steps

2 (- y + 1) = (\frac{1}{2} (x - 1))^{2}

Rewrite

2 (- y + 1) = (\frac{1}{2} (x - 1))^{2}

in the standard form

4 (- 2) (y - 0) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 0), p = - 2

16 x^{2} + 16 y + 96 x - 40 y = 315

x^{2} + (y - 32 x) 2 = 1

y - \frac{x}{y} = 1

y = - x^{2} + 4 x + 7

y^{2} - 4 x - 2 y + 9 = 0

What is 2(-y+1)=(1/2 (x-1))^2 ?
The solution to 2(-y+1)=(1/2 (x-1))^2 is Parabola with (h,k)=(1,0),p=-2