What is the eccentricity (x^2)/4-(y^2)/4 =1 ?

The eccentricity (x^2)/4-(y^2)/4 =1 is square root of 2

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eccentricity (x^2)/4-(y^2)/4 =1

eccentricity

\frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1

2

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 2

= \frac{2 ^{2} + 2 ^{2}}{2}

Refine

= 2

\frac{( x - 2 ) ^{2}}{9} - (y + 1)^{2} = 1

+ x^{2} - y^{2} = 4

y^{2} - 4 y - 4 x^{2} + 13 = 0

+ \frac{y ^{2}}{25} - \frac{x ^{2}}{4} = 1

9 y^{2} - 4 x^{2} = 36

What is the eccentricity (x^2)/4-(y^2)/4 =1 ?
The eccentricity (x^2)/4-(y^2)/4 =1 is square root of 2