What is the eccentricity (x^2)/4-(y^2)/9 =1 ?

The eccentricity (x^2)/4-(y^2)/9 =1 is (sqrt(13))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity (x^2)/4-(y^2)/9 =1

eccentricity

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1

\frac{13}{2}

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 3

= \frac{2 ^{2} + 3 ^{2}}{2}

Refine

= \frac{13}{2}

25 x^{2} + 10922 x - 25 y^{2} - y^{2} = 1439

16 x^{2} - 9 y^{2} + 32 x + 72 y - 704 = 0

16 y^{2} - 32 y - 9 x^{2} - 18 x = 137

\frac{x ^{2}}{a ^{2}} - \frac{y ^{2}}{b ^{2}} = 1

\frac{y ^{2}}{4} - (x + 1)^{2} = 1

What is the eccentricity (x^2)/4-(y^2)/9 =1 ?
The eccentricity (x^2)/4-(y^2)/9 =1 is (sqrt(13))/2