What is the center ((x-3)^2)/(8^2)-((y-2)^2)/(8^2)=1 ?

The center ((x-3)^2)/(8^2)-((y-2)^2)/(8^2)=1 is (3,2)

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center ((x-3)^2)/(8^2)-((y-2)^2)/(8^2)=1

center

\frac{( x - 3 ) ^{2}}{8 ^{2}} - \frac{( y - 2 ) ^{2}}{8 ^{2}} = 1

(3, 2)

Solution steps

\frac{( x - 3 ) ^{2}}{8 ^{2}} - \frac{( y - 2 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 2), a = 8, b = 8

And the center is:

(3, 2)

What is the center ((x-3)^2)/(8^2)-((y-2)^2)/(8^2)=1 ?
The center ((x-3)^2)/(8^2)-((y-2)^2)/(8^2)=1 is (3,2)