What is the center 4x^2-9y^2=36 ?

The center 4x^2-9y^2=36 is (0,0)

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center 4x^2-9y^2=36

center

4 x^{2} - 9 y^{2} = 36

(0, 0)

Solution steps

4 x^{2} - 9 y^{2} = 36

Rewrite

4 x^{2} - 9 y^{2} = 36

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 2

And the center is:

(0, 0)

4 x^{2} - \frac{1}{2} y^{2} + 8 x - 2 y = 2

4 x^{2} - 9 y^{2} + 3 x + 18 y + 91 = 0

\frac{( x + 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

9 x^{2} - 25 y^{2} = 225

- 4 x^{2} + y^{2} + 16 x + 12 y + 16 = 0