What is the center 11x^2-25y^2+22x+250y-889=0 ?

The center 11x^2-25y^2+22x+250y-889=0 is (-1,5)

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center 11x^2-25y^2+22x+250y-889=0

center

11 x^{2} - 25 y^{2} + 22 x + 250 y - 889 = 0

(- 1, 5)

Solution steps

11 x^{2} - 25 y^{2} + 22 x + 250 y - 889 = 0

Rewrite

11 x^{2} - 25 y^{2} + 22 x + 250 y - 889 = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{5 ^{2}} - \frac{( y - 5 ) ^{2}}{( 11 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 5), a = 5, b = 11

And the center is:

(- 1, 5)

16 x^{2} - 9 y^{2} - 144 = 0

x^{2} - 3 y^{2} - 2 x - 6 y + 7 = 0

9 (x - 1)^{2} - 16 (y + 2)^{2} = 144

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

\frac{y ^{2}}{4} - \frac{x ^{2}}{9} = 1

What is the center 11x^2-25y^2+22x+250y-889=0 ?
The center 11x^2-25y^2+22x+250y-889=0 is (-1,5)