What is the center 2x^2-2y^2-20x+16y+16=0 ?

The center 2x^2-2y^2-20x+16y+16=0 is (5,4)

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center 2x^2-2y^2-20x+16y+16=0

center

2 x^{2} - 2 y^{2} - 20 x + 16 y + 16 = 0

(5, 4)

Solution steps

2 x^{2} - 2 y^{2} - 20 x + 16 y + 16 = 0

Rewrite

2 x^{2} - 2 y^{2} - 20 x + 16 y + 16 = 0

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{1 ^{2}} - \frac{( y - 4 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 4), a = 1, b = 1

And the center is:

(5, 4)

- \frac{( x - 3 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{9} = 1

9 y^{2} - x^{2} + 2 x + 54 y + 62 = 0

x^{2} - 4 y^{2} + 8 x + 16 y - 4 = 0

\frac{x ^{2}}{9} - \frac{y ^{2}}{4} = 1

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 5 ) ^{2}}{9} = 1

What is the center 2x^2-2y^2-20x+16y+16=0 ?
The center 2x^2-2y^2-20x+16y+16=0 is (5,4)