asymptoten 4x^2-y^2+16x+6y=9

Lösung

asymptoten

4 x^{2} - y^{2} + 16 x + 6 y = 9

y = 2 (x + 2) + 3, y = - 2 (x + 2) + 3

Schritte zur Lösung

y = \pm \frac{b}{a} (x - h) + k

Calculate Hyperbola properties

4 x^{2} - y^{2} + 16 x + 6 y = 9 :

Right-left Hyperbola with

(h, k) = (- 2, 3), a = 2, b = 4

y = \frac{4}{2} (x - (- 2)) + 3, y = - \frac{4}{2} (x - (- 2)) + 3

Fasse zusammen

y = 2 (x + 2) + 3, y = - 2 (x + 2) + 3