What is the asymptotes of (y^2)/4-(x^2)/(25)=1 ?

The asymptotes of (y^2)/4-(x^2)/(25)=1 is y=(2x)/5 ,\quad y=-(2x)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of (y^2)/4-(x^2)/(25)=1

asymptotes

\frac{y ^{2}}{4} - \frac{x ^{2}}{25} = 1

y = \frac{2 x}{5}, y = - \frac{2 x}{5}

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

\frac{y ^{2}}{4} - \frac{x ^{2}}{25} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 5

y = \frac{2}{5} (x - 0) + 0, y = - \frac{2}{5} (x - 0) + 0

Refine

y = \frac{2 x}{5}, y = - \frac{2 x}{5}

\frac{x ^{2}}{3} - \frac{y ^{2}}{3} = 1

x^{2} - y^{2} = 4 x

- 16 x^{2} + 9 y^{2} + 96 x - 90 y - 63 = 0

- 4 x^{2} + y^{2} = 16

\frac{x ^{2}}{64} - \frac{y ^{2}}{144} = 1

What is the asymptotes of (y^2)/4-(x^2)/(25)=1 ?
The asymptotes of (y^2)/4-(x^2)/(25)=1 is y=(2x)/5 ,\quad y=-(2x)/5