What is the foci (x^2)/(625)-(y^2)/(3600)=1 ?

The foci (x^2)/(625)-(y^2)/(3600)=1 is (65,0),(-65,0)

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foci (x^2)/(625)-(y^2)/(3600)=1

foci

\frac{x ^{2}}{625} - \frac{y ^{2}}{3600} = 1

(65, 0), (- 65, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{625} - \frac{y ^{2}}{3600} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 25, b = 60

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2 5^{2} + 6 0^{2} : 65

(0 + 65, 0), (0 - 65, 0)

Refine

(65, 0), (- 65, 0)

5 x^{2} - 4 y^{2} - 40 x + 24 y + 24 = 0

\frac{y ^{2}}{25} - \frac{x ^{2}}{64} = 1

9 y^{2} + 36 y - 4 x^{2} - 32 x - 64 = 0

16 y^{2} + 64 y - x^{2} + 2 x = 1

- x^{2} + 9 y^{2} + 90 y + 189 = 0

What is the foci (x^2)/(625)-(y^2)/(3600)=1 ?
The foci (x^2)/(625)-(y^2)/(3600)=1 is (65,0),(-65,0)