What is the foci (x^2)/(37)-(y^2)/(63)=1 ?

The foci (x^2)/(37)-(y^2)/(63)=1 is (10,0),(-10,0)

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foci (x^2)/(37)-(y^2)/(63)=1

foci

(10, 0), (- 10, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{37} - \frac{y ^{2}}{63} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 37, b = 37

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 37^{2} + (37)^{2} : 10

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

What is the foci (x^2)/(37)-(y^2)/(63)=1 ?
The foci (x^2)/(37)-(y^2)/(63)=1 is (10,0),(-10,0)