What is the foci 9x^2-9y^2+18x+36y=63 ?

The foci 9x^2-9y^2+18x+36y=63 is (-1+2sqrt(2),2),(-1-2sqrt(2),2)

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foci 9x^2-9y^2+18x+36y=63

foci

9 x^{2} - 9 y^{2} + 18 x + 36 y = 63

(- 1 + 22, 2), (- 1 - 22, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - 9 y^{2} + 18 x + 36 y = 63 :

Right-left Hyperbola with

(h, k) = (- 1, 2), a = 2, b = 2

(- 1 + c, 2), (- 1 - c, 2)

Compute

c :

c = 2^{2} + 2^{2} : 22

(- 1 + 22, 2), (- 1 - 22, 2)

\frac{( y - 1 ) ^{2}}{\frac{1}{4}} - \frac{( x + 1 ) ^{2}}{\frac{1}{16}} = 1

64 y^{2} - 4 x^{2} = 256

4 x^{2} - y^{2} - 24 x + 20 = 0

\frac{( x + 3 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{16} = 1

9 x^{2} - y^{2} - 54 x - 2 y - 1 = 0

What is the foci 9x^2-9y^2+18x+36y=63 ?
The foci 9x^2-9y^2+18x+36y=63 is (-1+2sqrt(2),2),(-1-2sqrt(2),2)