What is the foci x^2-4y^2-2x+16y=20 ?

The foci x^2-4y^2-2x+16y=20 is (7/2 ,2),(-3/2 ,2)

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foci x^2-4y^2-2x+16y=20

foci

(\frac{7}{2}, 2), (- \frac{3}{2}, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - 4 y^{2} - 2 x + 16 y = 20 :

Right-left Hyperbola with

(h, k) = (1, 2), a = 5, b = \frac{5}{2}

(1 + c, 2), (1 - c, 2)

Compute

c :

c = 5^{2} + (\frac{5}{2})^{2} : \frac{5}{2}

(1 + \frac{5}{2}, 2), (1 - \frac{5}{2}, 2)

Refine

(\frac{7}{2}, 2), (- \frac{3}{2}, 2)

What is the foci x^2-4y^2-2x+16y=20 ?
The foci x^2-4y^2-2x+16y=20 is (7/2 ,2),(-3/2 ,2)