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foci
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Calculate Hyperbola properties
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foci ((y+3)^2}{16}-\frac{(x+1)^2)/9 =1foci 4x^2-9y^2+3x+18y+91=0foci 4x^2-25y^2=100foci (y^2)/3-(x^2)/3 =1foci y^2-x^2= 4/25
Frequently Asked Questions (FAQ)
What is the foci 25y^2-4x^2=100 ?
The foci 25y^2-4x^2=100 is (0,sqrt(29)),(0,-sqrt(29))