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Beliebt Geometry >

foki ((x+3)^2)/4-((y+1)^2)/(16)=1

Lösung

foki

\frac{( x + 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{16} = 1

Lösung

(- 3 + 25, - 1), (- 3 - 25, - 1)

Schritte zur Lösung

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{( x + 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{16} = 1 :

Right-left Hyperbola with

(h, k) = (- 3, - 1), a = 2, b = 4

(- 3 + c, - 1), (- 3 - c, - 1)

Compute

c :

c = 2^{2} + 4^{2} : 25

(- 3 + 25, - 1), (- 3 - 25, - 1)

Graph

Beliebte Beispiele

foki x^2-y^2=-4

f oc i x^{2} - y^{2} = - 4

foki-4x^2+y^2-16x-52=0

f oc i - 4 x^{2} + y^{2} - 16 x - 52 = 0

foki (y^2)/9-(x^2)/1 =1

f oc i \frac{y ^{2}}{9} - \frac{x ^{2}}{1} = 1

foki ((x-3)^2)/(16)-((y+4)^2)/(25)=1

f oc i \frac{( x - 3 ) ^{2}}{16} - \frac{( y + 4 ) ^{2}}{25} = 1

foki 4x^2-8y^2=3

f oc i 4 x^{2} - 8 y^{2} = 3