What is the foci 8x^2-2y^2=16 ?

The foci 8x^2-2y^2=16 is (sqrt(10),0),(-sqrt(10),0)

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foci 8x^2-2y^2=16

foci

(10, 0), (- 10, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

8 x^{2} - 2 y^{2} = 16 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 22

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + (22)^{2} : 10

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

What is the foci 8x^2-2y^2=16 ?
The foci 8x^2-2y^2=16 is (sqrt(10),0),(-sqrt(10),0)