What is the foci ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 ?

The foci ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 is (-1,4+sqrt(29)),(-1,4-sqrt(29))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

foci ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1

foci

(- 1, 4 + 29), (- 1, 4 - 29)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 1 ) ^{2}}{4} = 1 :

Up-down Hyperbola with

(h, k) = (- 1, 4), a = 5, b = 2

(- 1, 4 + c), (- 1, 4 - c)

Compute

c :

c = 5^{2} + 2^{2} : 29

(- 1, 4 + 29), (- 1, 4 - 29)

What is the foci ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 ?
The foci ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 is (-1,4+sqrt(29)),(-1,4-sqrt(29))