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foci
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Calculate Hyperbola properties
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foci (y^2)/(36)-(x^2)/(81)=1foci ((x-1)^2)/4-((y+2)^2)/1 =1foci 9x^2-y^2-54x-2y+71=0foci 25x^2+56476x-25y^2-3y=48838foci x^2-(y^2)/9 =1
Frequently Asked Questions (FAQ)
What is the foci 25y^2-9x^2=225 ?
The foci 25y^2-9x^2=225 is (0,sqrt(34)),(0,-sqrt(34))