What is the foci (x^2)/(25)-(y^2)/(64)=1 ?

The foci (x^2)/(25)-(y^2)/(64)=1 is (sqrt(89),0),(-sqrt(89),0)

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foci (x^2)/(25)-(y^2)/(64)=1

foci

(89, 0), (- 89, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{25} - \frac{y ^{2}}{64} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 8

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} + 8^{2} : 89

(0 + 89, 0), (0 - 89, 0)

Refine

(89, 0), (- 89, 0)

What is the foci (x^2)/(25)-(y^2)/(64)=1 ?
The foci (x^2)/(25)-(y^2)/(64)=1 is (sqrt(89),0),(-sqrt(89),0)