What is the foci (x^2)/9-(y^2)/7 =1 ?

The foci (x^2)/9-(y^2)/7 =1 is (4,0),(-4,0)

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foci (x^2)/9-(y^2)/7 =1

foci

(4, 0), (- 4, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{9} - \frac{y ^{2}}{7} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 7

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 7^{2} : 4

(0 + 4, 0), (0 - 4, 0)

Refine

(4, 0), (- 4, 0)

What is the foci (x^2)/9-(y^2)/7 =1 ?
The foci (x^2)/9-(y^2)/7 =1 is (4,0),(-4,0)