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vertices
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Calculate Hyperbola properties
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Popular Examples
vertices ((x^2))/(36)-((y^2))/(25)=1vertices 16x^2-y^2-64x-2y+47=0vertices (y^2)/(4^2)-(x^2)/(3^2)=1vertices ((y+2)^2)/4-((x-1)^2)/(45)=1vertices (x^2)/(729)-(y^2)/(484)=1
Frequently Asked Questions (FAQ)
What is the vertices (y^2}{36}-\frac{x^2)/4 =1 ?
The vertices (y^2}{36}-\frac{x^2)/4 =1 is (0,6),(0,-6)