What is the vertices (x^2)/(27)-(y^2)/(72)=1 ?

The vertices (x^2)/(27)-(y^2)/(72)=1 is (3sqrt(3),0),(-3sqrt(3),0)

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vertices (x^2)/(27)-(y^2)/(72)=1

vertices

(33, 0), (- 33, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{27} - \frac{y ^{2}}{72} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 33, b = 62

(0 + 33, 0), (0 - 33, 0)

Refine

(33, 0), (- 33, 0)

What is the vertices (x^2)/(27)-(y^2)/(72)=1 ?
The vertices (x^2)/(27)-(y^2)/(72)=1 is (3sqrt(3),0),(-3sqrt(3),0)