What is the vertices ((y-4)/4)^2-((x-6)/4)^2=1 ?

The vertices ((y-4)/4)^2-((x-6)/4)^2=1 is (6,8),(6,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

vertices ((y-4)/4)^2-((x-6)/4)^2=1

vertices

(6, 8), (6, 0)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

(\frac{y - 4}{4})^{2} - (\frac{x - 6}{4})^{2} = 1 :

Up-down Hyperbola with

(h, k) = (6, 4), a = 4, b = 4

(6, 4 + 4), (6, 4 - 4)

Refine

(6, 8), (6, 0)

What is the vertices ((y-4)/4)^2-((x-6)/4)^2=1 ?
The vertices ((y-4)/4)^2-((x-6)/4)^2=1 is (6,8),(6,0)