What is the vertices+((y-2)^2)/9-((x-1)^2)/(16)=1 ?

The vertices+((y-2)^2)/9-((x-1)^2)/(16)=1 is (1,5),(1,-1)

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vertices+((y-2)^2)/9-((x-1)^2)/(16)=1

vertices

+ \frac{( y - 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{16} = 1

(1, 5), (1, - 1)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

+ \frac{( y - 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{16} = 1 :

Up-down Hyperbola with

(h, k) = (1, 2), a = 3, b = 4

(1, 2 + 3), (1, 2 - 3)

Refine

(1, 5), (1, - 1)

- 4 x^{2} + y^{2} = 4

4 x^{2} - y^{2} - 16 x - 6 y - 9 = 0

4 x^{2} - 9 y^{2} = 144

f (x) f (x) = 3 (x + 6) (x + 3)

4 x^{2} - 9 y^{2} - 16 x + 18 y - 7 = 0

What is the vertices+((y-2)^2)/9-((x-1)^2)/(16)=1 ?
The vertices+((y-2)^2)/9-((x-1)^2)/(16)=1 is (1,5),(1,-1)