What is the vertices 7x^2-9y^2-14x+72y-200=0 ?

The vertices 7x^2-9y^2-14x+72y-200=0 is (4,4),(-2,4)

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vertices 7x^2-9y^2-14x+72y-200=0

vertices

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

(4, 4), (- 2, 4)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0 :

Right-left Hyperbola with

(h, k) = (1, 4), a = 3, b = 7

(1 + 3, 4), (1 - 3, 4)

Refine

(4, 4), (- 2, 4)

- 4 x^{2} + y^{2} = 16

x^{2} - y^{2} + 6 x - 4 y - 4 = 0

16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0

\frac{x ^{2}}{36} - \frac{y ^{2}}{81} = 1

\frac{( y - 1 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

What is the vertices 7x^2-9y^2-14x+72y-200=0 ?
The vertices 7x^2-9y^2-14x+72y-200=0 is (4,4),(-2,4)