Solution

vertices

Solution

Solution steps
Calculate Hyperbola properties
Right-left Hyperbola with
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Popular Examples

vertices (x^2}{49}-\frac{(y+6)^2)/4 =1vertices 5y^2-16x^2+400=0vertices ((x-5)^2)/1-((y-4)^2)/1 =1vertices ((y)^2)/(40)-((x)^2)/(81)=1vertices (x^2)/(25)-(y^2)/(121)=1

Frequently Asked Questions (FAQ)

  • What is the vertices 25x^2-16y^2+50x-32y-391=0 ?

    The vertices 25x^2-16y^2+50x-32y-391=0 is (3,-1),(-5,-1)