What is the vertices 16y^2-25x^2=400 ?

The vertices 16y^2-25x^2=400 is (0,5),(0,-5)

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vertices 16y^2-25x^2=400

vertices

16 y^{2} - 25 x^{2} = 400

(0, 5), (0, - 5)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

16 y^{2} - 25 x^{2} = 400 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 4

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

\frac{( x - 6 ) ^{2}}{48} - (y - 2)^{2} = 1

x^{2} - \frac{y ^{2}}{25} = 1

\frac{x ^{2}}{49} - \frac{y ^{2}}{4} = 1

y^{2} - 25 x^{2} + 8 y - 9 = 0

x^{2} - 16 y^{2} = 144

What is the vertices 16y^2-25x^2=400 ?
The vertices 16y^2-25x^2=400 is (0,5),(0,-5)