What is the vertices (y^2)/(12^2)-(x^2)/(5^2)=1 ?

The vertices (y^2)/(12^2)-(x^2)/(5^2)=1 is (0,12),(0,-12)

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vertices (y^2)/(12^2)-(x^2)/(5^2)=1

vertices

\frac{y ^{2}}{1 2 ^{2}} - \frac{x ^{2}}{5 ^{2}} = 1

(0, 12), (0, - 12)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{1 2 ^{2}} - \frac{x ^{2}}{5 ^{2}} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 12, b = 5

(0, 0 + 12), (0, 0 - 12)

Refine

(0, 12), (0, - 12)

x^{2} - 4 y^{2} = 4

64 x^{2} + 128 x - 9 y^{2} - 72 y - 656 = 0

\frac{x ^{2}}{4} - \frac{y ^{2}}{12} = 1

9 y^{2} - 4 x^{2} - 36 y - 8 x = 4

4 x^{2} - 25 y^{2} = 100

What is the vertices (y^2)/(12^2)-(x^2)/(5^2)=1 ?
The vertices (y^2)/(12^2)-(x^2)/(5^2)=1 is (0,12),(0,-12)