What is the vertices (x^2)/(49)-y^2=1 ?

The vertices (x^2)/(49)-y^2=1 is (7,0),(-7,0)

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vertices (x^2)/(49)-y^2=1

vertices

\frac{x ^{2}}{49} - y^{2} = 1

(7, 0), (- 7, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{49} - y^{2} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 7, b = 1

(0 + 7, 0), (0 - 7, 0)

Refine

(7, 0), (- 7, 0)

\frac{( y - 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

\frac{x ^{2}}{81} - \frac{y ^{2}}{144} = 1

\frac{y ^{2}}{36} - \frac{x ^{2}}{16} = 1

64 x^{2} - 100 y^{2} = 6400

x^{2} = y^{2} + 1

What is the vertices (x^2)/(49)-y^2=1 ?
The vertices (x^2)/(49)-y^2=1 is (7,0),(-7,0)