What is the vertices ((x-5)^2)/(81)-((y-7)^2)/(49)=1 ?

The vertices ((x-5)^2)/(81)-((y-7)^2)/(49)=1 is (14,7),(-4,7)

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vertices ((x-5)^2)/(81)-((y-7)^2)/(49)=1

vertices

\frac{( x - 5 ) ^{2}}{81} - \frac{( y - 7 ) ^{2}}{49} = 1

(14, 7), (- 4, 7)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{( x - 5 ) ^{2}}{81} - \frac{( y - 7 ) ^{2}}{49} = 1 :

Right-left Hyperbola with

(h, k) = (5, 7), a = 9, b = 7

(5 + 9, 7), (5 - 9, 7)

Refine

(14, 7), (- 4, 7)

\frac{x ^{2}}{25} - \frac{y ^{2}}{64} = 1

x^{2} - 4 y^{2} = 16

9 x^{2} - y^{2} - 54 x - 2 y + 71 = 0

\frac{y ^{2}}{25} - \frac{x ^{2}}{36} = 1

y^{2} - 4 x^{2} = 36

What is the vertices ((x-5)^2)/(81)-((y-7)^2)/(49)=1 ?
The vertices ((x-5)^2)/(81)-((y-7)^2)/(49)=1 is (14,7),(-4,7)