What is the vertices ((x-1)^2)/4-((y-1)^2)/4 =1 ?

The vertices ((x-1)^2)/4-((y-1)^2)/4 =1 is (3,1),(-1,1)

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vertices ((x-1)^2)/4-((y-1)^2)/4 =1

vertices

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{4} = 1

(3, 1), (- 1, 1)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (1, 1), a = 2, b = 2

(1 + 2, 1), (1 - 2, 1)

Refine

(3, 1), (- 1, 1)

\frac{y ^{2}}{4} - \frac{x ^{2}}{1} = 1

\frac{( y + 3 ) ^{2}}{25} - \frac{( x - 2 ) ^{2}}{49} = 1

\frac{y ^{2}}{15} - \frac{x ^{2}}{1} = 1

x^{2} - 4 y^{2} + 8 x + 16 y - 4 = 0

9 y^{2} - 4 x^{2} + 32 x - 36 y - 64 = 0

What is the vertices ((x-1)^2)/4-((y-1)^2)/4 =1 ?
The vertices ((x-1)^2)/4-((y-1)^2)/4 =1 is (3,1),(-1,1)