What is the vertices x^2-(y^2)/4 =1 ?

The vertices x^2-(y^2)/4 =1 is (1,0),(-1,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices x^2-(y^2)/4 =1

vertices

x^{2} - \frac{y ^{2}}{4} = 1

(1, 0), (- 1, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

x^{2} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 1, b = 2

(0 + 1, 0), (0 - 1, 0)

Refine

(1, 0), (- 1, 0)

\frac{y ^{2}}{25} - \frac{x ^{2}}{144} = 1

4 x^{2} - 9 y^{2} - 24 x - 36 y - 36 = 0

9 x^{2} - 25 y^{2} = 225

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1

\frac{x ^{2}}{4} - \frac{y ^{2}}{5} = 1

What is the vertices x^2-(y^2)/4 =1 ?
The vertices x^2-(y^2)/4 =1 is (1,0),(-1,0)