What is 7x^2-4x=10-2h(x) ?

The solution to 7x^2-4x=10-2h(x) is Parabola with (h,k)=(2/7 , 37/7),p=-1/14

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7x^2-4x=10-2h(x)

7 x^{2} - 4 x = 10 - 2 h (x)

(h, k) = (\frac{2}{7}, \frac{37}{7}), p = - \frac{1}{14}

Solution steps

7 x^{2} - 4 x = 10 - 2 y

Rewrite

7 x^{2} - 4 x = 10 - 2 y

in the standard form

4 (- \frac{1}{14}) (y - \frac{37}{7}) = (x - \frac{2}{7})^{2}

Therefore parabola properties are:

(h, k) = (\frac{2}{7}, \frac{37}{7}), p = - \frac{1}{14}

y^{2} + 18 y - 2 x = - 84

8 y^{2} + 64 y + 32 x - 48 = 0

y^{2} + x - 9 = 0

y - 3 x^{2} + 2 x - 36 \leq 0

x^{(2)} - 10 x + 8 y + 33 = 0

What is 7x^2-4x=10-2h(x) ?
The solution to 7x^2-4x=10-2h(x) is Parabola with (h,k)=(2/7 , 37/7),p=-1/14