What is y^2=(16-x^2)/(-4) ?

The solution to y^2=(16-x^2)/(-4) is Hyperbola with (h,k)=(0,0),a=4,b=2

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y^2=(16-x^2)/(-4)

y^{2} = \frac{16 - x ^{2}}{- 4}

(h, k) = (0, 0), a = 4, b = 2

Solution steps

y^{2} = \frac{16 - x ^{2}}{- 4}

Rewrite

y^{2} - \frac{16 - x ^{2}}{- 4} = 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 2

(\frac{x + 1}{36})^{2} - (\frac{y - 4}{64})^{2} = 1

\frac{( x - 3 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{64} = 1

4 x^{2} - 5 y^{2} - 36 y - 36 = 0

y^{2} - 1 = 16 (x^{2} - 1)

5 x^{2} - 4 y^{2} - 18 y + 9 = 0

What is y^2=(16-x^2)/(-4) ?
The solution to y^2=(16-x^2)/(-4) is Hyperbola with (h,k)=(0,0),a=4,b=2