What is ((y+5)^2)/(25)-((x-6)^2)/(16)=1 ?

The solution to ((y+5)^2)/(25)-((x-6)^2)/(16)=1 is Hyperbola with (h,k)=(6,-5),a=5,b=4

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((y+5)^2)/(25)-((x-6)^2)/(16)=1

\frac{( y + 5 ) ^{2}}{25} - \frac{( x - 6 ) ^{2}}{16} = 1

(h, k) = (6, - 5), a = 5, b = 4

Solution steps

\frac{( y + 5 ) ^{2}}{25} - \frac{( x - 6 ) ^{2}}{16} = 1

Rewrite

\frac{( y + 5 ) ^{2}}{25} - \frac{( x - 6 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 5 ) ) ^{2}}{5 ^{2}} - \frac{( x - 6 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (6, - 5), a = 5, b = 4

2 x^{2} - 3 y^{2} = 15

\frac{( x + 3 ) ^{2}}{1} - \frac{( y + 3 ) ^{2}}{3} = 1

(x - 9)^{2} - 9 (y + 7)^{2} = 1

4 x^{2} - 9 y^{2} + 24 x - 36 y - 36 = 0

\frac{x ^{2}}{4} - (\frac{( y + 1 )}{16})^{2} = 1

What is ((y+5)^2)/(25)-((x-6)^2)/(16)=1 ?
The solution to ((y+5)^2)/(25)-((x-6)^2)/(16)=1 is Hyperbola with (h,k)=(6,-5),a=5,b=4