What is ((x-3)^2)/(36)-((y-1)^2)/(16)=1 ?

The solution to ((x-3)^2)/(36)-((y-1)^2)/(16)=1 is Hyperbola with (h,k)=(3,1),a=6,b=4

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((x-3)^2)/(36)-((y-1)^2)/(16)=1

\frac{( x - 3 ) ^{2}}{36} - \frac{( y - 1 ) ^{2}}{16} = 1

(h, k) = (3, 1), a = 6, b = 4

Solution steps

\frac{( x - 3 ) ^{2}}{36} - \frac{( y - 1 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 3 ) ^{2}}{36} - \frac{( y - 1 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{6 ^{2}} - \frac{( y - 1 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 1), a = 6, b = 4

16 x^{2} - 25 y^{2} + 256 x + 150 y + 399 = 0

y^{2} - x^{2} + y - x - 14 = 0

9 x^{2} - 4 y^{2} - 90 x - 32 y + 125 = 0

\frac{28}{x + y} + \frac{24}{x - y} = 6

4 x^{2} = 10 + y^{2}

What is ((x-3)^2)/(36)-((y-1)^2)/(16)=1 ?
The solution to ((x-3)^2)/(36)-((y-1)^2)/(16)=1 is Hyperbola with (h,k)=(3,1),a=6,b=4